Question

58. The escape velocity of a body from the earth is u. What is the escape velocity
from a planet whoso mass and radius are twice those of the earth​

Answer 1

Step-by-step explanation:

the lowest velocity which a body must have in order to escape the gravitational attraction of particular planet or other object

Answer 2

Answer:

v

Step-by-step explanation:

v=sqrt(2*gM/r)

M=2*M

r=2*r

v=sqrt(2*GM/r)=sqrt(2*G*2*M/(2*r))=v

twice the radius is 8 times the volume twice the mass density is 1/4 of earth