Question

580-[18 of 1]-{16*14+(270÷9)-38+68)}]​

Answer 1

solution:-580-[18*1]-{16*14+(270/9)-38+68}

=580-18-{224+30+30}

=580-18-284

=580-302

=278 ans

I hope it helps you

plz.. mark brainliest

Answer 2

Answer:

The value of 580-[18 of 1]-{[16*14+(270/9)-38+68}] is 278.

Step-by-step explanation:

• Addition is the process of adding two or more items together.
• The operation or process of finding the difference between two numbers or quantities is known as subtraction.
• Multiplication is a method of finding the product of two or more numbers.
• Division is a process of splitting a specific amount into equal parts.

BODMAS is also known as PEDMAS which stands for Parentheses, Exponents, Division, Multiplication, Addition, and Subtraction. According to BODMAS rule, the brackets have to be solved first followed by powers or roots (i.e. of), then Division, Multiplication, Addition, and at the end Subtraction.

For finding the value of given equation we follow BODMAS or PEDMAS rule.

$580-[18 of 1]-{[16*14+(270/9)-38+68}]$

Dividing $270/9=30$

$=580-[18 * 1]-[{16*14+(30)-38+68)}]$

Multiplying $18*1=18$, $16*14=224$, $68-38=30$

$=580-[18 ]-{[{224+(30)+30}}]$

Addition $224+30+30=284$

$=580-18 -{[284]$

$=580-302$

$=278$

To solve more sums on BODMAS go to the following link:

https://brainly.in/question/3982019

To solve more sums related to addition, subtraction go to the following link:

https://brainly.in/question/51879253

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