Question

588.38 g of sweets have to be made into Sweet balls of each 45.26 grams weight.how many such sweet balls can be prepared?​

Answer 1

Answer:

refer to the attached file......!!!!!

Answer 2

Answer: 13 Sweet balls

Step-by-step explanation:

No .of sweet balls which can be prepared = $\frac{Total.weight.of . sweets }{Weight. of .one. sweetball}$

                                                                     = $\frac{588.38 g}{45.26g}$

                                                                     = 13 Sweet balls

Thank U : )