Question

59*59*59-9*9*9÷59*59+59*9+9*9=50 prove that

Answer 1

let 59=a
and 9=b


a^3-b^3

Answer 2

Answer:

a=59

b=9

a^3-b^3/a^2+b^2+ab=50

                                                                   a^3-b^3=(a-b)(a^2+b^2+ab)

(a-b)(a^2+b^2+ab)/a^2+b^2+ab=50

(a^2+b^2+ab) gets canceled

a-b=50

substitute value of a and b

59-9=50

Step-by-step explanation: