Question

59
7. A 10 V cell of negligible internal resistance is connected in parallel across a battery of emf 200 V and
internal resistance 38 W as shown in the figure. Find the value of current in the circuit.
10 V
3822
200 V​

Answer 1

Answer:

We have the equation :

V = E-Ir

where V is the terminal voltage, E is the emf of the cell ,I is the current and r is the internal resistance.

GIVEN:

V=10 V E=200 V r =38 ohm I=?

V=E-Ir

I= E-V/r

200-10 /38

190/38

I =5A