Question

59. A ball hitted by a batsman with a
velocity 20 m/s by making an angle
60° to the horizontal then what is
maximum height
1 m
5 m
10 m
15 m​

Answer 1

Answer:

A cricketer hits a ball with a velocity 25 m/s at 60

0

above the horizontal. How far above the ground it passes over a fielder 50 m from the bat (assume the ball is struck very close to the ground)

Explanation:

Equation of trajectory when a projectile is thrown with velocity u at an angle θ with the horizontal is

y=xtanθ−

2

1

u

2

cos

2

θ

gx

2

y=50tan60

0

−

2

1

×

25×25×[

2

1

]

2

9.8×50×50

=50

3

=9.8×8

=86.60−78.4=8.2m