59. A car is moving on a straight road with uniform
acceleration. The speed of the car varies with time as
follows:
Time (s) : 0 2 4 6 8 10
Speed (m/s) : 4 8 12 16 20 24
Draw the speed-time graph by choosing a convenient
scale. From this graph:
Calculate the acceleration of the car.
i) Calculate the distance travelled by the car in 10 second
Answers
so the scale will be
on x axis 1cm=2sec
on y axis 1cm = 4 m/s
acceleration of car is 2m/s²
distance covered in 10ssec is 140 m
(i) Acc(i) Acceleration of the car = slope of AB=
10−0
24−4
=
10
20
=2m/s
2
(ii) Distance travelled by the car in 10s= area of trapezium OABC
=
2
1
×(OA+BC)×OC
=
2
1
×(4+24)×10=140m
solutioneleration of the car = slope of AB=
10−0
24−4
=
10
20
=2m/s
2
(ii) Distance travelled by the car in 10s= area of trapezium OABC
(i) Acceleration of the car = slope of AB=
10−0
24−4
=
10
20
=2m/s
2
(ii) Distance travelled by the car in 10s= area of trapezium OABC
=
2
1
×(OA+BC)×OC
=
2(i) Acceleration of the car = slope of AB=
10−0
24−4
=
10
20
=2m/s
2
(ii) Distance travelled by the car in 10s= area of trapezium OABC
=
2
1
×(OA+BC)×OC
=
2
1(i) Acceleration of the car = slope of AB=
10−0
24−4
=
10
20
=2m/s
2
(ii) Distance travelled by the car in 10s= area of trapezium OABC
=
2
1
×(OA+BC)×OC
=
2
1
×(4+24)×10=140m
solution
×(4+24)×10=140m
solution
1
×(4+24)×10=140m
solution
=
2
1
×(OA+BC)×OC
=
2
1
×(4+24)×10=140m
solution
Answer:
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Class 11
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>>A car is moving on a straight road with
Question
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A car is moving on a straight road with uniform acceleration. The speed of the car varies with time as follows :
Time(s): 0 2 4 6 8 10
Speed (m/s): 4 8 12 16 20 24
Draw the speed-time graph by choosing a convenient scale. From this graph :
(i) Calculate the acceleration of car.
(ii) Calculate the distance travelled by the car in 10 seconds.
Medium
Solution
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(i) Acceleration of the car = slope of AB=
10−0
24−4
=
10
20
=2m/s
2
(ii) Distance travelled by the car in 10s= area of trapezium OABC
=
2
1
×(OA+BC)×OC
=
2
1
×(4+24)×10=140m