Question

59. A metal rod having a coefficient of linear expansion of 2x10*/Chas a length of 100cm
at 20°C. The temperature at which it is shortened by Imm is
1. 40°C 2. -30°C 3. -20°C 4. – 10°C​

Answer 1

Answer:

The temperature of the rod is

$T = -30^o C$

Explanation:

As we know that if temperature of the solid rod is increased then due to thermal expansion its length will increase

Here we know that the coefficient of thermal expansion is given as

$\alpha = 2 \times 10^{-5}$

here we know by the formula

$\Delta L = L \alpha \Delta T$

here we will plug in all data into it

$0.1 = 100 (2\times 10^{-5})\Delta T$

$10^{-3} = 2 \times 10^{-5}\Delta T$

$\Delta T = 50$

so we have

$20 - T = 50$

$T = -30^o C$

#Learn

Topic : thermal expansion

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