Physics, asked by 99dipti16, 5 months ago

59. Fig. 2.41 shows a network of resistances.
The effective resistance between points A
and B of the network is
3 Ω
3 Ω
ww

6 Ω
M

w
6 Ω
3 Ω
A

B​

Answers

Answered by anubhabkumar2020
0

Answer:

Answer:

Answer:

Answer: L=2m,

Answer: L=2m,d=3mm,A=

Answer: L=2m,d=3mm,A= 4

Answer: L=2m,d=3mm,A= 49π

Answer: L=2m,d=3mm,A= 49π

Answer: L=2m,d=3mm,A= 49π ×10

Answer: L=2m,d=3mm,A= 49π ×10 −6

Answer: L=2m,d=3mm,A= 49π ×10 −6 m

Answer: L=2m,d=3mm,A= 49π ×10 −6 m 2

Answer: L=2m,d=3mm,A= 49π ×10 −6 m 2

Answer: L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL=

Answer: L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 4

Answer: L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π

Answer: L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π

Answer: L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10

Answer: L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6

Answer: L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10

Answer: L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11

Answer: L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11

Answer: L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2

Answer: L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2

Answer: L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2 =8.48×10

Answer: L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2 =8.48×10 −5

Answer: L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2 =8.48×10 −5 m=0.085mm

Answer: L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2 =8.48×10 −5 m=0.085mm

Answer: L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2 =8.48×10 −5 m=0.085mm .

Answer: L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2 =8.48×10 −5 m=0.085mm .

Answer: L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2 =8.48×10 −5 m=0.085mm .

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