Question

59. In /\ABC, AD bisects angle BAC and AD = DC. If angle BOA = 70° then the measure of angle ABD is:​

Answer 1

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given: AD-DC

Hence angle dac-angle dca =x(say)

we know that the exterior angle is equal

to sum of its opposite interior angle

hence, angle ADB-angle (dac+dca)

70=x+ X

x=35

and angle bad-angle dac = 35°

Now, in triangle ABD we have

70°+35°+angle ABD=180°

angle ABD=180°-105°-75°

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Answer 2

Answer:

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