Question

(5a+2) (a+4) your answer should be a polynomials in standard form​

Answer 1

Answer:

5a^2+22a+8

Step-by-step explanation:

=(5a+2) (a+4)

= 5a^2+20a+2a+8

=5a^2+22a+8. ans

Answer 2

Answer:

5a² + 22a + 8

Note:

★ Standard form of any polynomial is written in descending order of degree ( power ) of the variable .

★ The standard form of a quadratic polynomial is given as ; ax² + bx + c .

★ The possible values of the variable for which the polynomial becomes zero are called its zeros.

★ In order to find the zeros of the given polynomial , equate it to zero .

★ A quadratic polynomial can have atmost two zeros .

Solution:

Here,

The given polynomial is :

(5a + 2)(a + 4)

Now,

=> (5a + 2)(a + 4)

=> 5a(a + 4) + 2(a + 4)

=> 5a² + 20a + 2a + 8

=> 5a² + 22a + 8

Hence,

The given polynomial in its standard form is : 5a² + 22a + 8 .

°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°

Moreover,

In order to find the zeros of the given polynomial , let's equate it to zero .

Thus,

=> (5a + 2)(a + 4) = 0

=> 5a + 2 = 0 OR a + 4 = 0

=> 5a = -2 OR a = -4

=> a = -2/5 OR a = -4

Hence,

The zeros of the given polynomial are :

a = -2/5 , -4