Question

5a−[2b−{4c−(6a−2b+3c−2a)}]​

Answer 1

Answer:

5a-[2b-{4c-6a+2b-3c+2a}]

=5a-[2b-{c-4a+2b}]

=5a-[2b-c+4a-2b]

=5a-[4a-c]

=5a-4a+c

=a+c

Answer 2

Answer:

a + c

Step-by-step explanation:

5a −[2b −{4c −(6a − 2b + 3c −2a)}]

= 5a −[2b −{4c −(4a − 2b +3c)}]

= 5a −[2b −{4c - 4a +2b - 3c}]

= 5a −[2b −{c - 4a +2b }]

= 5a −[2b - c + 4a - 2b ]

= 5a - [4a - c]

= 5a - 4a + c

= a + c

$\bf \pmb{\bold{ \red{Note:}}}$

(+) × (+) = (+)

(-) × (-) = (+)

(+) × (-) = (-)

(-) × (+) = (-)