Question

5a-4a square +3 solve thise q​

Answer 1

Answer:

a+3................................

Answer 2

Answer:

x=25+11−−√i5

x=25−11−−√i5

which becomes

x=0.4+0.663325i

x=0.4−0.663325i

Solution by completing the square for:

5x2−4x+3=0

a≠1 so divide through by 5

55x2−45x+35=05

which gives us

x2−45x+35=0

Keep x terms on the left and move

the constant to the right side

by subtracting it on both sides

x2−45x=−35

Take half of the x term and square it

[−45⋅12]2=425

then add the result to both sides

x2−45x+425=−35+425

Rewrite the perfect square on the left

(x−25)2=−35+425

and combine terms on the right

(x−25)2=−1125

Take the square root of both sides

x−25=±−1125−−−−√

Simplify the Radical term (0):

x−25=±11−−√i5

Isolate the x on the left side and

solve for x (1)

x=25±11−−√i5

therefore (2)

x=25+11−−√i5

x=25−11−−√i5

which becomes

x=0.4+0.663325i

x=0.4−0.663325i