Math, asked by priyankanigam836, 8 months ago

5a^m(5b^m)^2/(a^2m)²

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Answered by Anonymous
3

Answer:

SOLUTION

2m2 – 5m = 0,

\[m = 2, \frac{5}{2}\]

When m = 2

\[2 \left( 2 \right)^2 - 5\left( 2 \right) = 0\]

\[ \Rightarrow 8 - 10 = 0\]

\[ \Rightarrow - 2 \neq 0\]

So, m = 2 is not a solution of the given equation.

When \[m = \frac{5}{2}\]

\[2 \left( \frac{5}{2} \right)^2 - 5\left( \frac{5}{2} \right) = 0\]

\[ \Rightarrow \frac{25}{2} - \frac{25}{2} = 0\]

So,

\[m = \frac{5}{2}\] is a solution of the given quadratic equation.

Thus, only \[m = \frac{5}{2}\] is a root of the given quadratic equation.

Concept: Solutions of Quadratic Equations by Factorization

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Chapter 2: Quadratic Equations - Practice Set

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