Math, asked by asmi48871, 11 months ago

5a²+10a+5 factorisation

Answers

Answered by Arshalan
15

Answer:

5a² + 10a +5

5a² + 5a +5a + 5 =0

5a(a+1) + 5(a+1) =0

(a+1) (5a+5) =0

a = -1

a=-5/5 = -1

hope it will help u

Answered by Anonymous
1

Answer:

5a {}^{2}  + 10a + 5 = 0 \\ 5a {}^{2}  + 5a + 5a + 5 = 0 \\ 5a(a + 1) + 5(a + 1) = 0 \\ (a + 1)(5a + 5) = 0 \\ a =  - 1 \: and \:  - 1

hope it helps you

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