Math, asked by KUNJALKADU, 3 months ago

5a²-22a-15=0
how to solve it​

Answers

Answered by snehaprajnaindia204
12

Answer:

5 {a}^{2}  - 22a - 15 = 0 \\  \\  =  > 5 {a}^{2}  - 25a  + 3a - 15 = 0 \\  \\  =  > 5a(a - 5) + 3(a - 5) = 0 \\  \\  =  > (5a + 3) \times (a - 5) = 0 \\  \\  =  > (5a + 3) = 0 \:  \: or \:  \:( a - 5) = 0 \\  \\  =  > a =  \frac{ - 3}{5}  \:  \: o r \:  \: a = 5

Answered by Anonymous
61

Answer:

\begin{lgathered}5 {a}^{2} - 22a - 15 = 0 \\ \\ = > 5 {a}^{2} - 25a + 3a - 15 = 0 \\ \\ = > 5a(a - 5) + 3(a - 5) = 0 \\ \\ = > (5a + 3) \times (a - 5) = 0 \\ \\ = > (5a + 3) = 0 \: \: or \: \:( a - 5) = 0 \\ \\ = > a = \frac{ - 3}{5} \: \: o r \: \: a = 5\end{lgathered}

Similar questions