Question

5a²+2b. solve withe the formula of (a+b)²​

Answer 1

Question :-

Solve using the Formula $\bf (a + b)^2 = a^2 + 2ab + b^2$

(i) $(5a + 2b)^2$

Solution :-

We have :

$\begin {aligned} (5a + 2b)^2 & = (5a)^2 + 2 \times 5a \times 2b + (2b)^2\\\\& = 25a^2 + 20ab + 4b^2\\\\\therefore\: \bold {(5a + 2b)^2} & = \bf 25a^2 + 20ab + 4b^2 \end {aligned}$

Additional Information :-

Some more Formulae for Factorization:

$\boxed {\begin {minipage}{6.5 cm} (1) (a - b)^2 = (a^2 - 2ab + b^2)\\\\(2) (a^2 - b^2) = (a + b)(a - b)\\\\(3) (x + a)(x + b) = x^2 + (a + b) \times x + ab \end {minipage}}$

Answer 2

Question

5a^2 +2b

Answer

GIVEN :-

• 5a^2+2b

TO FIND :-

• the value of the identity by the formula(a+b)^2

Solution :-

$\rightarrow \sf \gray{(5a + b) ^{2} }$

$\rightarrow \sf{ \gray{(5a) ^{2} + 2(5a)(2b) + 2b ^{2} }}$

$\rightarrow { \sf \gray{25 {a}^{2} + 20ab + 4 {b}^{2} }}$

• Hence, the value of (5a+b)^2 = 25a^2+20ab+4b^2 .

More to know ;

• IDENTITY I :-
• $\sf(x + y) ^{2} = {x}^{2} + {y}^{2} + 2xy$
• IDENTITY ii :-
• $\sf(x - y )^{2} = {x}^{2} + {y}^{2} - 2xy$
• IDENTITY III :-
• $\sf {x}^{2} - {y}^{2} = (x + y)(x - y)$
• IDENTITY IV :-
• $\sf(x + a)(x + b) = {x}^{2} + (a + b)x + ab$