Question

5a² b²-30ab+10a² b³ by (-5ab²) ​

Answer 1

Answer:

Let a+b=x .

Then (a+b)2=a2+b2+2ab=x2

⟹2ab=x2–7 ……………….(1)

Also (a+b)3=a3+b3+3ab(a+b)=x3.

⟹10+3ab(x)=x3.

⟹10+3(x2–72)(x)=x3.

or x3–21x+20=0.

Solving we get a+b=x=1,4,−5.

Now, we can find a and b for each corresponding value of x.