Question

5a²b² (7c -21) ÷ 15 ab (c-3)​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

when we multiply then :

35a²b²c - 105a²b² / 15abc - 45ab

then here is common :

5ab ( 7abc - 21ab) / 5ab ( 3c-9)

the 5ab cut each other :

then in left no... common no. are

7ab ( c-3)/

3(c-3) = 7AB/ 3