(5ab-3)(5ab+2),Expand the given equation.
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(5ab-3)(5ab+2)
= 5ab (5ab+2) - 3(5ab+2)
= 25a²b² + 10ab - 15ab -6
= 25a²b² - 5ab - 6
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BONJOUR,
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![(5ab - 3)(5ab + 2) \\ 5ab(5ab + 2) - 3(5ab + 2) \\ 25a {}^{2} b {}^{2} + 10ab - 15ab - 6 \\ 25a {}^{2} b {}^{2} - 5ab - 6 (5ab - 3)(5ab + 2) \\ 5ab(5ab + 2) - 3(5ab + 2) \\ 25a {}^{2} b {}^{2} + 10ab - 15ab - 6 \\ 25a {}^{2} b {}^{2} - 5ab - 6](https://tex.z-dn.net/?f=%285ab+-+3%29%285ab++%2B+2%29+%5C%5C+5ab%285ab+%2B+2%29+-+3%285ab+%2B+2%29+%5C%5C+25a+%7B%7D%5E%7B2%7D+b+%7B%7D%5E%7B2%7D++%2B+10ab++-+15ab++-+6+%5C%5C+25a+%7B%7D%5E%7B2%7D+b+%7B%7D%5E%7B2%7D+-+5ab+-+6+)
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