Question

5@2#3=335, 7@8#1=203, 2@9#5=608, then 3@2#7=


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Answer 1

Given :  5@2#3=335, 7@8#1=203, 2@9#5=608,

To Find :  3@2#7=

Solution:

5@2#3=335,

523 - Reverse 325

325 + 3 + 2 + 5  = 335

7@8#1=203,

781  reverse  187

187 + 1 + 8 + 7  = 203

2@9#5=608,

295 reverse 592

592 + 5 + 9 + 2 =  608

 3@2#7=

327 reverse 723

723 + 7 + 2 + 3   = 735

 3@2#7= 735

Logic is

x@y#z   = zyx + z + y + x   where  x , y &z  are digits

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