Question

5bags and 7 books together cost Rs. 2350. While 4 books and 10 bags cost

Rs. 2200, find the cost of each bag?​

Answer 1

Answer:

Let, Bags = x, Books = y

5 Bags and 7 books cost Rs.2350 i.e,

5x+7y=2350-----(1)

4 Books and 10 Bags cost 2200 i.e,

10x+4y=2200-----(2)

By solving,

x=175,y=250

Cost of each Bag is 175/-

Answer 2

The cost of each bag is Rs. 120.

----------------------------------------------------------------------------------------

Let's solve the given problem:

Let's say that,

"x" → Cost of 1 bag

"y" → Cost of 1 book

5 bags and 7 books together cost Rs. 2350, so we can form an equation as,

$5x + 7y = 2350 \:.\:.\:.\:(1)$

4 books and 10 bags together cost Rs. 2200, so we can form another equation as,

$10x + 4y = 2200 \:.\:.\:.\:(2)$

On multiplying equation (1) by 10, we get

$[5x + 7y = 2350 \:.\:.\:.\:(1) ] \times 10$

$\implies 50x + 70 y = 23500 \:.\:.\:.\:(3)$

On multiplying equation (2) by 5, we get

$[10x +4y = 2200 \:.\:.\:.\:(1) ] \times 5$

$\implies 50x + 20 y = 11000 \:.\:.\:.\:(4)$

On subtracting equation (4) from (3), we get

$50x + 70 y = 23500\\50x + 20 y = 11000\\-\:\:\:\:\:-\:\:\:\:\:\:\:\:\:\:-\\---------\\\:\:\:50y = 12500\\---------$

∴ $\bold{y} = \frac{12500}{50} = \bold{250}$ ← Cost of 1 book

On substituting y - 250 in equation (1), we get

$5x + (7\times 250) = 2350$

$\implies 5x + 1750 = 2350$

$\implies 5x = 600$

$\implies \bold{x = 120}$

Thus, the cost of each bag is Rs. 120.

--------------------------------------------------------------------------------

Learn more on brainly.in:

brainly.in/question/45521212

brainly.in/question/43198995