(5C0)(50C6)-(5C1)(40C6)+(5C2)(30C6)-(5C3)(20C6)+(5C4)(10C6)
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Given: (5C0)(50C6)-(5C1)(40C6)+(5C2)(30C6)-(5C3)(20C6)+(5C4)(10C6)
To find: Solve the above combination.
Solution:
- So, to solve this combination we have the formula:
a C 2b = a ! / ( a− b ) ! b !
- So, by using this formula, we get:
= 5 ! / ( 5− 0 ) ! 0 ! x 50 ! / ( 50− 6 ) ! 6 ! - 5 ! / ( 5− 1 ) ! 1 ! x 40 ! / ( 40− 6 ) ! 6 ! + 5 ! / ( 5− 2 ) ! 2 ! x 30 ! / ( 30− 6 ) ! 6 ! - 5 ! / ( 5− 3 ) ! 3 ! x 20 ! / ( 20− 6 ) ! 6 ! + 5 ! / ( 5− 4 ) ! 4 ! x 10 ! / ( 10− 6 ) ! 6 !
- Now simplifying the terms step by step we get:
= 15890700 - 5(3838380) + 10(593775) - 10(38760) + 5(210)
= 15890700 - 19191900 + 5937750 - 387600 + 1050
= 2250000
Answer:
So the value of the combination is 2250000.
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