5cm high object is placed at a distance of 25cm from converging lens of focal length of 10cm. Determine the position size and type of image
Answers
1/f=1/v-1/u...................formula
f=25cm and u=5cm.then by applying this in the formula we get,
1/25-1/10=1/f
by solving this we get v=16.66cm
real and inverted image will be formed on the other side of the lens at 16.66cm fro its optic centre
Answer:
16.7cm, 3.3cm, Real
Explanation:
Given :
Height of object, ho = 5cm
Object distance, u = - 25cm
Since the lens is converging, thus it is a convex lens.
Focal length of the lens, f = 10cm
Using lens formula,
1/v - 1/u = 1/f
= 1/v = 1/10 + 1/ - 25 = 3/50
= v = 50/3 = 16.7cm
Thus, the image is formed 16.7cm right of the lens.
Now we know,
v/u = hi/ho
= hi = 50/ 3 × - 25 × 5 = 10/3 = - 3.
Thus, the size of the image is 3.3cm.
Negative sign shows that the image formed is real and inverted. Hence, the image formed is real and inverted and diminished.