Question

5cos^2 60°+4cos^2 30°-tan^2 45°÷sin^2 30°+cos^2 60°

Answer 1

Hope it helps. :) just substitute the values

Answer 2

Answer:

$\frac{13}{2}$

Or 6.5

Explanation:

The value of 5cos²60°+4cos²30°-tan²45°÷sin²30°+cos²60°

=$\frac{5\times\left(\frac{1}{2}\right)^{2}+4\times\left(\frac{\sqrt{3}}{2}\right)^{2}-1^{2}}{\left(\frac{1}{2}\right)^{2}+\left(\frac{1}{2}\right)^{2}}$

= $\frac{5\times\left(\frac{1}{4}\right)+4\times\left(\frac{3}{4}\right)-1}{\left(\frac{1}{4}\right)+\left(\frac{1}{4}\right)}$

=$\frac{\frac{5}{4}+\frac{12}{4}-1}{\frac{2}{4}}$

=$\frac{\frac{5+12-4}{4}}{\frac{2}{4}}$

= $\frac{\frac{17-4}{4}}{\frac{2}{4}}$

= $\frac{\frac{13}{4}}{\frac{2}{4}}$

=$\frac{13}{2}$

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