Question

5Cos^2 60°+4Sec^2 30°-Tan^2 45° ÷ Sin^2 30° + Cos^2 30°​

Answer 1

Answer:

67/12. is the answer......

Step-by-step explanation:

explanation in attachment...

Answer 2

Answer:

$\frac{5cos {}^{2}60° \:+ 4sec {}^{2}30° \: - tan {}^{2}45° \: }{sin {}^{2}30° \: - tan {}^{2}45° \: }$

= $\frac{5 \times ( \frac{1}{2}) {}^{2} \: + 4 \times ( \frac{2}{ \sqrt{3} } ) {}^{2} - 1 {}^{2} }{1}$( Since, cos²Ѳ + sin²Ѳ = 1 )

= $\frac{5}{4} + \frac{16}{3} - 1$

= $\frac{15 + 64 - 12}{12}$

= $\frac{67}{12}$