5cos A - 12sin A = 0
evaluate sin A + cos A / 2cos A - sin A
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5 cos A = 12 sin A
.'. Your question says sin A + cos A = sinA + 12/5 sinA = 17sinA / 5
Also, 2cosA - sinA = 24/5 sinA - sinA = 19 sinA/5
Dividing both, we have:- (sin A + cos A)/(2cosA - sinA) = 17 / 19
5 cos A = 12 sin A
.'. Your question says sin A + cos A = sinA + 12/5 sinA = 17sinA / 5
Also, 2cosA - sinA = 24/5 sinA - sinA = 19 sinA/5
Dividing both, we have:- (sin A + cos A)/(2cosA - sinA) = 17 / 19
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