Question

5cos A=4 find tanA and cosecA

Answer 1

Answer:

$5\cos(a) = 4 \\ \cos(a) = \frac{4}{5} \\ then \\ \sin(a) = \sqrt{1 - { { \cos }^{2} a} } \\ \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt{1 - \frac{16}{25} } \\ \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt{ \frac{25 - 16}{25} } = \sqrt{ \frac{9}{25} } = \frac{3}{5}$

$\tan(a) = \frac{ \sin(a) }{ \cos(a) } = \frac{3 \div 5}{4 \div 5} = \frac{3}{4} \\ and \: \: \: \\ \cosec(a) = \frac{1}{ \sin(a) } = \frac{1}{\frac{3}{5} } = \frac{5}{3}$

hope this will help u....

Answer 2

Given:–

CosA=$\frac{4}{5}$

To find:–

TanA and Cosec A

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$\pink{\boxed{\blue{\underline{\green{\mathrm{Proof:-}}}}}}$

CosA=$\frac{Adjacent side}{Hypotenuse}$

TanA=$\frac{SinA}{CosA}$=>$\frac{3}{4}$

CosecA=$\frac{Hypotenuse}{Opposite side}$=>$\frac{5}{3}$

★Refer Attachment For further Details★

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