5cos theta=3 तो 3tan theta =?
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cosФ = 3/5
P.S. You can do this directly if you know cos53° = 3/5
Ф=53°
⇒tanФ = tan53° = 4/3
3tanФ = 4
Now if you don't know the above then,
cosФ = 3/5
sinФ = √(1-cos²Ф) = √(1-9/25) = 4/5
tanФ = 4/3
3tanФ = 4
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