Question

5cos0°-2sin30°+√3cos30°\tan30°×tan60°×cos60° +3sin29°sec61​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

value of given expression is 13/7

(5cos0° - 2sin0° + √3cos30°)/(tan30°. tan60° . cos60° + 3sin29°. sec61°)

we know, cos0° = 1, sin0° = 0

cos30° = √3/2 , tan30° = √3

tan60° = √3,cos60° = 1/2 and cos30° = √3/2

we also know, sin(90 - x) = cosx

so, sin29° = sin(90 - 61) = cos61°

now, (5cos0° - 2sin0° + √3cos30°)/(tan30°. tan60° . cos60° + 3sin29°. sec61°)

= (5 × 1 - 2 × 0 + √3× √3/2)/(1/√3 × √3 × 1/2 + 3 cos61°. sec61°)

= (5 + 3/2)/(1/2 + 3 )

= (13/2)/(7/2)

= 13/7

also read : Find the value of tan60°-tan30°/1+tan60°-tan30°?

https://brainly.in/question/3127771

Sin30°- Sin90°+2Cos0°/Tan30°•Tan60°

https://brainly.in/question/2510720