Math, asked by johnmohanta372, 11 months ago

5cos² 60°+4sec²30°-tan²45°/sin²30°+cos²30°

Answers

Answered by sophysherry
5

cos 60°= 1/2

sec 30°= 2/√3

tan 45°= 1

sin 30°= 1/2

cos 30°= √3/2

5cos^2 60°+4sec^2 30° -tan^2 45°/sin^2 30°

+cos^2 30°

5(1/2)^2 +4(2/√3)^2 - (1)^2 /(1/2)^2+(√3/2)^2

5×1/4 + 4×4/3 - 1/ 1/4+ 3/4

5/4 + 16/3 - 1 / 4/4

15/12 + 64/12 - 1 /1

79/12-1

79/12 - 12/12 = 67/12

Hope this helps

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