5cos²45+4sin⁴60+ 3tan²45
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cos45° =1/√2
sin60°= √3/2
tan45° =1
substituting these values,
5×(1/√2)² + 4×(√3/2)⁴ +3×1
=5/2 +9/4 +3
=31/4
sin60°= √3/2
tan45° =1
substituting these values,
5×(1/√2)² + 4×(√3/2)⁴ +3×1
=5/2 +9/4 +3
=31/4
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