5cosA-12sinA=0,then find the value of sinA +cosA/2cosA-sinA
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Answered by
139
5cosA-12sinA=0
or, 5cosA=12sinA
or, cosA=12/5sinA
∴, (sinA+cosA)/(2cosA-sinA)
={sinA+(12/5)sinA}/{2×(12/5)sinA-sinA}
=(5sinA+12sinA)/5]/[(24sinA-5sinA)/5]
=17sinA/5×5/19sinA
=17/19
or, 5cosA=12sinA
or, cosA=12/5sinA
∴, (sinA+cosA)/(2cosA-sinA)
={sinA+(12/5)sinA}/{2×(12/5)sinA-sinA}
=(5sinA+12sinA)/5]/[(24sinA-5sinA)/5]
=17sinA/5×5/19sinA
=17/19
Answered by
51
Answer:
Therefore the final answer is 17/19 ...
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