5cosA-3A=0 find tan
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Answer:
√(25 - 9A²) / 3A
Step-by-step explanation:
5CosA - 3A = 0
CosA = 3A/5 = Adjacent side to A /Hypotenuse
Cos²A + Sin²A = 1
Sin²A = 1 - (3A/5)² = 25 - 9A²/25
SinA = √(25 - 9A²) / 5
TanA = SinA/CosA = √(25 - 9A²) / 5 / 3A/5 = √(25 - 9A²) / 5 * 5/3A
=√(25 - 9A²) / 3A
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