5cosx+12sinx=13 find sinx in hindi
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Answered by
2
5cox + 12sinx = 13
cosx = √1-sin^2x
5√(1-sin^2x) + 12sinx = 13
5√(1-sin^2x) = 13 - 12sinx
let sinx = t
squaring both sides
25(1-t^2) = 169 + 144t^2- 2*13*12t
25 - 25t^2 = 169 + 144t^2 - 312t
119t^2 - 312t + 144 = 0
solve for t then substitute
t = sinx
cosx = √1-sin^2x
5√(1-sin^2x) + 12sinx = 13
5√(1-sin^2x) = 13 - 12sinx
let sinx = t
squaring both sides
25(1-t^2) = 169 + 144t^2- 2*13*12t
25 - 25t^2 = 169 + 144t^2 - 312t
119t^2 - 312t + 144 = 0
solve for t then substitute
t = sinx
Answered by
0
Answer:
Step-by-step explanation:
5sinx+12cosx=13
differentiate with respect to x
5(cosx)+12(-sinx)=0
5cosx-12sinx=0
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