Question

5g hydrogen react with 38g of oxygen to form water. Find the limiting reactant

Answer 1

Answer:

Explanation: In the given reaction,

H2 +O2= H2O

Let us write what is given to us about the quantities under the particular compounds,

H2 + O2= H2O

6g 32g 54g

Now let's write the real masses under the above mentioned equation and balance it.

2H2 +O2 = 2H2O

6g 32g 54g

2(2) 32 2(18) - (molecular weights)

Now limiting reagent is the substanve which gets completely used up in the reaction.

Thus applying unitary method and comparing the given masses with the molecular weights of the compounds, we can find the limiting reagent.

According to molecular weights,

4g of H2 require 32g of O2.

1g of H2 requires 32/4 g of O2.

=8g of O2.

But the given amount of H2 is 6g.

Thus 6g if H2 requires 6*8g of O2

=48g of O2.

Now comparing the calculated value with the given value of O2.

32g < 48g hence O2 is the limiting reagent

Given amount < required amount.