5g if ice at 0 degree is mixed with 5g of steam at 100 degree. What is final temperature
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Hey user !!
Here's the answer you are looking for
Let us assume that the 5g ice gains heat to converts to 5g water, and then it's temp rises to 100°C & the 5g steam loses heat to convert into water at 100°C.
If the heat loss and heat gain is same then our assumption is right.
(Please see the attachment for the calculations)
Since, the heat loss is very large and heat gain is comparatively very less in our assumption, it is not the answer.
So, to compensate this, some amount of steam will convert into water, so that the heat loss is less.
Let the Mass of steam that converts into water is m
so, 540m = 900
m = 900/540 = 1.667g
So, total Mass of water at 100°C = 5g + 1.667g = 6.667g
☛ So, the final temp. is 100°C with 6.67g of water and 3.33g of steam.
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
Let us assume that the 5g ice gains heat to converts to 5g water, and then it's temp rises to 100°C & the 5g steam loses heat to convert into water at 100°C.
If the heat loss and heat gain is same then our assumption is right.
(Please see the attachment for the calculations)
Since, the heat loss is very large and heat gain is comparatively very less in our assumption, it is not the answer.
So, to compensate this, some amount of steam will convert into water, so that the heat loss is less.
Let the Mass of steam that converts into water is m
so, 540m = 900
m = 900/540 = 1.667g
So, total Mass of water at 100°C = 5g + 1.667g = 6.667g
☛ So, the final temp. is 100°C with 6.67g of water and 3.33g of steam.
★★ HOPE THAT HELPS ☺️ ★★
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