Question

5g of hydrogen react with 23g of oxygen to form water .which is the limiting reagent and how many miles of water is formed?

Answer 1

Answer:

The limiting reagent in the reaction is oxygen.

Number of moles of water formed is 1.44 moles.

Explanation:

The balanced chemical equation for the reaction can be written as:

$2H_{2} +O_{2}$ → $2H_{2} O$

Given mass of hydrogen = 5 g

Molar mass of hydrogen = 2 g/mol

Number of moles of hydrogen = given mass ÷ molar mass

                                                   = $\frac{5}{2}$ = 2.5 moles

Given mass of oxygen = 23 g

Molar mass of oxygen = 32 g/mol

Number of moles of oxygen = given mass ÷ molar mass

                                               = $\frac{23}{32}$  =0.72 moles

According to the equation, 1 mole of oxygen combines with 2 moles of hydrogen to give 2 moles of water.

Number of moles of hydrogen needed = 0.72 × 2 =1.44 moles

But we have an excess amount of hydrogen.

Thus the limiting reagent is oxygen.

1 mole of oxygen gives 2 moles of water.

Thus 0.72 moles of oxygen gives 0.72 × 2 = 1.44 moles of water