Question

5g of ice at 0° c is mixed with the 5g of steam at 100° c the amount of water in the mixture will be​

Answer 1

Answer:

Heat energy required for5gm of water at 0

∘

Cto get converted to water at 100

∘

C is latent heat required + heat required to change its temperature by 100

∘

=(80⋅5)+(5⋅1⋅100)=900calories.

Now,heat liberated by 5gm of steam at 100

∘

C to get converted to water at 100

∘

C is 5⋅537=2685 calories

Explanation:

I hope it will help you!!