Question

5g of naoh is dissolve in enough water to make 112 g of solution ,whose density is 1.08 g/mole calculate the normality

Answer 1

Answer:

See below

Explanation:

Normality=number of equivalents/volume of solution

Now, number of equivalents=no. of moes*n-factor=5/40*1=0.125

And volume of soln = mass of soln/density of soln

=112/1.08

Find normality by the above 1st formula