Question

5g steam at 100 degree is passed into 6g ice at 0 degree find the final temp

Answer 1

Answer:

~45°C

Step-by-step explanation:

s = 1 (water)

m1 = 5g

m2 = 6g

T1 = 100°C = 373K

T2 = 0°C = 273K

final Temp = T

Heat absorb/transfer = Q = ms(T2-T1)

Q (steam) = 5 × 1 × (373-T) = 1875 - 5T

Q (ice) = 6 ×1 × (T-273) = 6T - 1638

now....

Q (steam) = Q (ice)

1865 - 5T = 6T - 1638

3503 = 11T

T = 318.45K ~ 45°C