Question

5gm mixture of Na2CO3 and CaCO3 is heated and mixture shows 1.32gm weight loss. Find mass percentage of Na2CO3 in the mixture​

Answer 1

Answer:

16g

Explanation:

mass percentage of Na2co3 is 16g

Answer 2

Given:

weight of Na$_2$CO$_3$  = 5 gm

weight of CaCO$_3$ = 5 gm

weight loss = 1.32gm

To find:

mass percentage of Na$_2$CO$_3$  =?

Step-to-step-explanation:

• Na$_2$CO$_3$ does not decompose on heating.
• CaCO$_3$  on heating gives CaO & CO$_2$.

         CaCO$_3$ + Δ → CaO + CO$_2$

• At first, we have to calculate the moles of CaCO$_3$ .

        Mole of CaCO$_3$  = $\displaystyle \frac{1}{2.5}$

• Now, we can calculate the weight of CaCO$_3$ my multiplying moles of CaCO$_3$  to 100.

        weight of CaCO$_3$ = moles of CaCO$_3$  × 100

                                     =  $\displaystyle \frac{1}{2.5}$  × 100

                                     = 40 gm

• The % of Na$_2$CO$_3$ from the mixture is given by

          % of Na$_2$CO$_3$ = $\displaystyle \frac{weight \ of\ CaCO_3}{weight \ of \ mixture}$

                                = $\displaystyle \frac{40}{5}$

                                = 8

• Hence the mass percentage of Na$_2$CO$_3$  in the mixture​ is 8%.