Question

5gm mixture of Na2CO3 and CaCO3 is heated and mixture shows 1.32gm weight loss. Find mass percentage of Na2CO3 in the mixture​

Answer 1

Explanation:

Only CaCO3 will decompose on heating.

CaCO3 > CaO + CO2

100 g = 22.4 litres of gas at NTP

22.4 litres of gas at NTP is produced by = 100 g

1.12 Litre of gas at NTP is produced by

= 100 x 1.12 / 22.4 = 5 g

% of CaCO3 = (5/20) × 100 = 25 %

% of Na2CO3 = 100 -25 = 75 %