5gm mixture of Na2CO3 and CaCO3 is heated and mixture shows 1.32gm weight loss. Find mass percentage of Na2CO3 in the mixture
Answers
Answered by
0
Explanation:
Only CaCO3 will decompose on heating.
CaCO3 > CaO + CO2
100 g = 22.4 litres of gas at NTP
22.4 litres of gas at NTP is produced by = 100 g
1.12 Litre of gas at NTP is produced by
= 100 x 1.12 / 22.4 = 5 g
% of CaCO3 = (5/20) × 100 = 25 %
% of Na2CO3 = 100 -25 = 75 %
Similar questions