5gm of anhydrons sodium carbonate is dissolve in 100ml of solution. find molarity
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Answer:
Calculate molarity of the following substance 5.3 gram of anhydrous sodium carbonate is dissolved in 100 ml of solution. 1. See answer.
Missing: 5gm | Must include: 5gm
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Explanation:
The molecular weight of Na2CO3 is 106 g/mol. Calculate the number of moles is represented by 5 g. This is EQUAL TO 5 g/106 g/mol or 0.0472 mol. MOLARITY= 0.0472 mol/0.2 L = 0.236 mol/L or 0.236 M.
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