Question

5gm sugar is present in 108 gm of water molar mass of sugar will be

Answer 1

Explanation:

Given: Wt. of solute (w)=1.71g

Molar mass of solute (m)=342

Volume of solution (v)=500ml=0.5lt

Temperature (T)=300K

Gas constant (R)=0.0821ltatmK

−1

mol

−1

Osmotic pressure (π)=

mV

wRT

=

342×0.5

1.71×0.0821×300

=0.25atm

Thus, Osmotic pressure of the solution is 0.25atm.

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Answer 2

Given:

Mass of sugar present in water= 5gm

Mass of water= 108gm

To Find:

The molar mass of sugar.

Solution:

• No. of moles (n) = Given mass÷ Molar mass

• Using this formula, we will find the following,

1. No. of moles of water (n∨1) = 108÷18

⇒ 6 moles

     2. Total no. of moles (n) = (108+5)÷ ( 18 + x )

⇒113÷(18+x)

• Here, x is the molar mass of sugar.

    3. No. of moles of sugar (n∨2) = (n - n∨1)

⇒(5÷x) = (113÷(18+x)) - 6

⇒6=(113÷(18+x)) - (5÷x)

On solving the equation further we get,

⇒x²= 15

∴ x = 3.87 gm/ mol.

Hence, the molar mass of sugar will be 3.87 gm/mol.