Question

5k of Nacl is disolve in I kg of water
calculate the molality of the solution​

Answer 1

ANSWER
∵ΔT=iK
b
​

W
A
​

n
​


Given,
K
b
​
=0.52 K kg mol
−1


n=1;W
A
​
=1 kg;i=2 since NaCl is electrolyte.

∴ΔT=
1
2×0.52×1
​
=1.04 K

∵ Boiling point of pure water at 1.013 bar(i.e., 1 atm) is 373.15 K

∴ Boiling point of the solution =373.15+1.04=374.19 K

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