5kg ball is thrown upward with a speed of 10m/s.Find the potential energy when it reaches the highest point
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m=5kg
u=10m/s
v=0m/s
g= -9.8 m/s^2
2gh=v^2-u^2
2* -9.8 * h = - 100
h= -100/2*-9.8
h= 5.102 m
potential energy= mgh
=5*9.8*5.102
=249.998 J
u=10m/s
v=0m/s
g= -9.8 m/s^2
2gh=v^2-u^2
2* -9.8 * h = - 100
h= -100/2*-9.8
h= 5.102 m
potential energy= mgh
=5*9.8*5.102
=249.998 J
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Answer:
Explanation:The answer is second class lever.
In second class levers, load lies between the fulcrum and the effort.
However, the load is not positioned at the exact center. It is placed more towards the fulcrum and away from the effort. A second class lever always multiplies a force.
There are many examples of second class levers in day to day life. Some common examples are bottle openers, nut crackers, doors and wheel barrows.
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