Math, asked by Shivani001, 1 year ago

5log2+3/2log25+1/2log49-log28

Answers

Answered by brunila
11
5log2 + 3/2log25 + 1/2log49 - log28
log32 + log(25)^3/2 + log(49)^1/2 - log28
log32 + log 5^3 + log7 - log28
log32 + log125 + log7 - log28
log(32 x 125 x 7  ) - log28
log(28000) - log28
log(28000/28)
log1000
log10^3 to the base 10
3
FORMULAE USED
mloga = loga^m
loga + logb = logab
loga - logb = log(a/b)

Answered by samprit51
0

Answer:

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