Math, asked by Anonymous, 10 months ago

5log25/24-3log80/81-7log15/16​

Answers

Answered by Anonymous
7

=5log(25/24)−3log(80/81)−7log(15/16)

=5log(25)−5log(24)−3log(80)+3log(81)−7log(15)+7log(16)

=5log(52)−5log(23∗3)−3log(24∗5)+3log(34)−7log(3∗5)+7log(24)

=10log5−15log2−5log3−12log2−3log5+12log3−7log3−7log5+28log2

=log2

Amannnscharlie

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