Math, asked by foreducation001, 10 months ago

5m -3n=19 eq (1)
m-6n=-7 eq (2)

Answers

Answered by gowshyasubhani
0

Answer:hope u the answer help u

Step-by-step explanation:

eq (1) =>5m-3n=19

eq(2)×5=>(m-6n=-7)×5

            =>5m-30n=-35

          eq(1)-eq(2)=>(5m-3n=19)-(5m-30n=-35)

                            =>5m-3n-5m+30n=19+35

                           =>-3n+30n=54

                          =>27n=54

                           =>n=54/27

                          =>n=2

substitute n=2 in eq (1)

5m-3n=19

5m-3×2=19

5m-6=19

5m=19+6

5m=25

m=25/5

m=5

Answered by BlackWizard
1

Answer:

5m – 3n = 19 .....(I)

m – 6n = –7 .....(II)

Multiplying (I) with 2 we get

10m – 6n = 38 .....(III)

m – 6n = –7 .....(IV)

Subtracting (IV) from (III) we get

10m-m-6n-(-6n)=38-(-7)

⇒9m=45

⇒m=45/9

=5

Putting the value of m = 5 in (II) we get

5-6n=-7⇒-6n=-7-5

⇒-6n=-12

⇒n=-12/-6

=2

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